From $var() design point of view, as @henningw said, it
is bringing more confusions, because $var() is always initialised.
But you can also add a new variable that you think it meets better your needs.
--
Reply to this email directly or view it on GitHub:
https://github.com/kamailio/kamailio/pull/3114#issuecomment-1128954853
You are receiving this because you are subscribed to this thread.
Message ID: <kamailio/kamailio/pull/3114/c1128954853(a)github.com>