According to https://www.kamailio.org/wiki/cookbooks/5.1.x/transformations (and I'm using 5.1), I should be able to do something like $var(num)=$(fU{s.substr,-1,10}) and $var(num) should be 123456789 if $fU is 0123456789 (only the last 10 characters are displayed). However, $var(num) ends up with only the last character of the substring, in this case, 9.

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