2 Jul
2018
2 Jul
'18
4:40 p.m.
Thanks John for the Reply.
So if i understand properly :
group 1 is here <sip:anonymous@
group 2 is empty
group 3 is ;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD
the previous expression is working for IPv4.
Now for IPv6
Input : From: <sip:anonymous@
[2008:abcd:1234:2260:208:5dff:fe93:5b65]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
subst('/^From:(.*)[2008:abcd:1234:2260:208:5dff:fe93:5b65](.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig');
Output : From:
<sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b6[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
//what is going wrong here?
Here
group 1 is <sip:anonymous@
group 2 is empty
group 3 is ;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
what mistake am i making for IPv6 ? if you see the output.
Regards,
Mahesh.b
On Mon, Jul 2, 2018 at 6:54 PM John Petrini <jpetrini(a)coredial.com> wrote:
They are references to groups in the regex match. The
groups are in
parenthesis. Whatever is matched by group 1 and 3 will be included in the
substitution.
https://regexr.com/ and https://regex101.com/ are both good sites for
building and explaining regexes.
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