I`ve solved this issue. The condition if ($Ru == «udp:10.130.0.23:5070»)  was wrong.

Here is the correct code:

       if ($Ru eq "sip:10.130.0.23:5070") {
                $fs = "udp:10.130.0.23:5060";
        } else {
                $fs = "udp:10.130.0.23:5070";
        }

пт, 1 июл. 2022 г. в 15:17, Алексей Якимкин <ayakimkin@gmail.com>:

Hello,

Are you ips (LAN_IP and WAN_IP) on sepparate interfaces?

I use add_path for Register requests. It insert header Path: <sip:10.130.0.23:5070;lr>

My pbx calls to User-Agent throught 10.130.0.23:5070. INVITE(from kamailio) go out  to internet from 10.130.0.23:5070

This line "$fs = «udp:10.130.0.23:5060»;" don`t work, It produces an error:

(pv [pv_branch.c:62]: pv_get_branchx_helper(): error accessing branch [0])

ср, 29 июн. 2022 г. в 18:55, ZZ Wave <zzwave@gmail.com>:

I use this with NATed Kamailio and Asterisk for "transparent" registrations:

        if (is_method("REGISTER")) {
            add_path();
        }
        if ($Ri=="LAN_IP") {
                $fs="udp:WAN_IP:5060";
        } else {
                $fs="udp:LAN_IP:5060";
        }

AFAIK FreeSwitch supports Path as well but Yate doesn't

ср, 29 июн. 2022 г. в 12:25, Алексей Якимкин <ayakimkin@gmail.com>:

Hello,

I have  kamailio in local network behind NAT. Kamailio have one interface eth1 with ip 10.130.0.23

UserAgent - (internet) - (178.0.0.169)router_with_NAT - (LAN) - kamailio+rtpproxy - pbx

I made two listeners:
listen=udp:10.130.0.23:5070 #to pbx in lan (I don`t want to put via header with 178.0.0.169)
listen=udp:10.130.0.23:5060 advertise 178.0.0.169:5060 #to internet (UserAgent need to get via header with 178.0.0.169  )

mhomed = 1 # I think It not useful  for my case

UserAgent send Register and Invite to 178.0.0.169:5060, Kamailio get it on udp:10.130.0.23:5060

Kamailio Relay it to   udp:10.130.0.23:5070

My pbx get requests from  udp:10.130.0.23:5070 with via header 10.130.0.23

Responses to UserAgent go from  udp:10.130.0.23:5060 with via 178.0.0.169

In  RELAY block:
if ($Ru == «udp:10.130.0.23:5070») {
#set_send_socket(«udp:10.130.0.23:5060»);
$fs = «udp:10.130.0.23:5060»;
#force_send_socket(«udp:10.130.0.23:5060»);
} else {
#set_send_socket(«udp:10.130.0.23:5070»);
$fs = «udp:10.130.0.23:5070»;
}
#$fs = «udp:10.130.0.23:5070»;
if (!t_relay()) {
sl_reply_error();
}

route[REGISTRAR] {

        if ($rd == "mydomain.ru" || $rd == "mydomain2.ru") {

          set_send_socket("udp:10.130.0.23:5070");

         }

}

It works for requests from UserAgent to PBX. But INVITE from my pbx to UserAgent goes only through udp:10.130.0.23:5070 ,  Kamailio realy it to internet from udp:10.130.0.23:5070

I get error in syslog:  (pv [pv_branch.c:62]: pv_get_branchx_helper(): error accessing branch [0])

I tried set_send_socket(«udp:10.130.0.23:5070»); and $fs = «udp:10.130.0.23:5070»;

Why I can`t relay outgoing requests to internet through another socket? 

--

Best regards,
Alex

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  * sr-users@lists.kamailio.org
Important: keep the mailing list in the recipients, do not reply only to the sender!
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--

С уважением,
Якимкин Алексей

--

С уважением,
Якимкин Алексей

__________________________________________________________
Kamailio - Users Mailing List - Non Commercial Discussions
  * sr-users@lists.kamailio.org
Important: keep the mailing list in the recipients, do not reply only to the sender!
Edit mailing list options or unsubscribe:
  * https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users