11 Jan
2007
11 Jan
'07
8:10 p.m.
I get the follwing response from openserctl show ul
~~~Contact(0x284a6880)~~~
domain : 'location'
aor : '1020111'
Contact : 'sip:1020111@192.168.0.198:5060'
Expires : 3592
q : Call-ID : '4ef617d2-8e70ad17(a)192.168.0.198'
CSeq : 4249
User-Agent: 'Linksys/SPA3102-5.1.5(GWa)'
received : 'sip:67.188.231.188:62292'
Path : ''
State : CS_DIRTY
Flags : 0
Sock : 66.224.20.35:5060 (0x8123fb0)
Methods : 5183
next : 0x0
prev : 0x0
~~~/Contact~~~~
Can anybody tell me the meaning of the CS_DIRTY state reply?
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