12 May
2016
12 May
'16
10:39 a.m.
Hi,
DBG_TLSF_MALLOC is defined if DBG_SR_MEMORY is defined
(mem/tlsf_malloc.h:25) , so in this case it assigns a
void* (*)(tlsf_t, size_t,
const char*, const char*, unsigned int, const char*)
to a
void* (*)(void*, unsigned long,
const char*, const char*, unsigned int, const char*)
I'm also compiling on Debian 8, x86_64-linux-gnu architecture, but
cannot see these warnings, whether I run
make MEMDBG=0 cfg
or
make MEMDBG=1 cfg
before compiling. My gcc version is 4.9.2 (Debian 4.9.2-10).
--
Camille
All I see is
that we are assigning a
void* (*)(tlsf_t, size_t)
to a
void* (*)(void* , unsigned long)
yet tlsf_t is defined as `typedef void* tlsf_t`, and size_t and
unsigned long have the same width on this architecture...
Is that true also when DBG_TLSF_MALLOC has been defined?