Hi All,
Kamailio send 2 INVITE(lookup rewrite r-uri and append branch) request for
Client behind NAT.
Due to this reason for one request,Client respond with 486 Busy here. we
only want to send 1 INVITE request.
Following are the AOR for client at kamailio.if field(ip port) in CONTACT
and RECEIVED differ then kamailio send 2 INVITE request.
FOLLOWING INVITE HAS BEEN GENERATED AFTER LOOKUP FUNCTION(one from contact
and one from Received field).
INVITE:sip:123@192.168.230.124:45672
INVITE:sip:123@204.192.206.208:45672
I want only ONE INVITE request to be generated.Please suggest how do solve
this issue or if there is any config change or any code change required to
achieve this?
AOR:: 123
Contact:: sip:123@192.168.230.124:45672 Q=1
Expires:: 894
Callid:: 003A8EC4-12351(a)192.168.230.124
Cseq:: 2
User-agent:: SIPPER for 3CX Phone
Received:: sip:204.192.206.208: 45672
State:: CS_NEW
Flags:: 0
Cflag:: 192
Socket:: udp:172.12.120.88:5060
Methods:: 4294967295
Ruid:: uloc-5aba112d-7fce-5
Reg-Id:: 0
Last-Keepalive:: 1522144583
Last-Modified:: 1522144583
thanks,
amit