27 Apr
2007
27 Apr
'07
8:34 a.m.
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Hi,
today I tried to use is_user_in like this:
if(is_user_in($avp(status), "r"))
{
}
I get this error on openser console:
0(6852) parse error (479,23-35): syntax error
0(6852) parse error (479,39-40): bad arguments
Line 479 is the if(is_user_in... line
regards
helmut
Helmut Kuper schrieb:
Helmut Kuper schrieb:
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Hello,
I tried to call is_user_in funktion with a
variable as group name. I
want to create the group name on the fly, when a INVITE arrives.
if(is_user_in("To", $var(a)))
{
...
}
I got this error message:
0(27274) xl_parse_svname: parsing [$var(a)]
0(27274) xl_lookup_spec_name: found [fu] [18]
0(27274) find_cmd_export_t: found <xlog>(2) in module xlog
[/home/hk/openser//lib/openser/modules/]
0(27274) parse error (479,27-34): syntax error
0(27274) parse error (479,34-35): bad arguments
wrong -> > Is there a way to do dynamic group names für is_user_id?
correct: Is there a way to do dynamic group names for is_user_in?
regards
helmut
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http://openser.org/cgi-bin/mailman/listinfo/users
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