12 Feb
2013
12 Feb
'13
9:28 a.m.
Hi
Thanks, what I actually need is keep numbers and * and # and remove the
rest, something like
$rU = $(rU{re.subst,/![0-9*#]//g});
But I am not sure that ! works for negation.
Regards
On Mon, Feb 11, 2013 at 5:43 PM, Daniel Tryba <daniel(a)pocos.nl> wrote:
On Monday 11 February 2013 11:24:36 Ali Jawad wrote:
*
*
I am using the below to strip "-" from
destination numbers, it does work
just fine "I replace - with nothing", what i need to do now is to strip
all
characters except 0-9 * and #. Is there anyway to
do it using the
following
configuration part
You are using regular expression substitution, so yes this can be done:
/[^0-9*#]//g
Take a look at http://en.wikipedia.org/wiki/Regular_expression
for more info.