[SR-Users] Using =~ to get the group identifier with longest match

Hi, I wonder how feasible is the folowing: I have a regular expresion like: REGEXP = "^((1|20)|(13|3|4)|(5|6))" There are 3 matching groups: 1) (1|20) 2) (13|3|4) 3) (5|6) I want to match the RURI user, let's suppose $rU = "138787686223". In this case the above regexp matches groups 1 and 2, but since group 2 matching is longest ("13" is longest than "1") I want to get value 2. In case $rU = "999999" I need to get "null", in case $rU = "1000022323" I need to get "1". AFAIK there is no way to do it with current regular expression utils in Kamailio, but maybe I miss something. Thanks a lot. -- Iñaki Baz Castillo <ibc(a)aliax.net>