6 Jun
2011
6 Jun
'11
8:25 a.m.
Hi, I wonder how feasible is the folowing:
I have a regular expresion like:
REGEXP = "^((1|20)|(13|3|4)|(5|6))"
There are 3 matching groups:
1) (1|20) 2) (13|3|4) 3) (5|6)
I want to match the RURI user, let's suppose $rU = "138787686223". In this case the above regexp matches groups 1 and 2, but since group 2 matching is longest ("13" is longest than "1") I want to get value 2.
In case $rU = "999999" I need to get "null", in case $rU = "1000022323" I need to get "1".
AFAIK there is no way to do it with current regular expression utils in Kamailio, but maybe I miss something. Thanks a lot.
--
Iñaki Baz Castillo
ibc@aliax.net