iirc, with that log message the rtpproxy is not starting if you don't provide the -u or -F parameter.
The netstat shows only kamailio as application, no rtpproxy. See if rtpproxy is in the process running table, like:
ps -auxw | grep -i rtpproxy
Cheers,
Daniel
YES, i think rtpproxy is running
root@ns3033789:/usr/local/src/kamailio-5.0/rtpproxy# netstat -np | grep 7722udp 0 0 127.0.0.1:43042 127.0.0.1:7722 ESTABLISHED 13084/kamailioudp 0 0 127.0.0.1:38992 127.0.0.1:7722 ESTABLISHED 13062/kamailioudp 0 0 127.0.0.1:47217 127.0.0.1:7722 ESTABLISHED 13093/kamailioudp 0 0 127.0.0.1:43185 127.0.0.1:7722 ESTABLISHED 13086/kamailioudp 0 0 127.0.0.1:49354 127.0.0.1:7722 ESTABLISHED 13113/kamailioudp 0 0 127.0.0.1:51461 127.0.0.1:7722 ESTABLISHED 13097/kamailioudp 0 0 127.0.0.1:43428 127.0.0.1:7722 ESTABLISHED 13065/kamailio
i started RTPproxy like this:
root@ns3033789:/usr/local/src/kamailio-5.0/rtpproxy# rtpproxy -l 5.135.177.203 -s udp:localhost:7722rtpproxy: running this program as superuser in a remote control mode is strongly not recommended, as it poses serious security threat to your system. Use -u option to run as an unprivileged user or -F is you want to run as a superuser anyway.
Keffa Y. Diomande
Skype : keffadi
Tel : +225 02 77 22 22
Office : Abidjan Ciad
http://www.alcall.net
Le 10 avr. 2017 à 09:11, Alex Balashov <abalashov@evaristesys.com> a écrit :
ascertained
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