26 Mar
2010
26 Mar
'10
4:29 p.m.
Hi Alex,
Actually what I'm trying to do is check the IPs on a request on a
Kamailio+RTPProxy acting as border of our network.
So I have the ingress IP and egress IP and need to check if I have to bridge
ii, ei, ie or ee.
I managed to obtain all IPs in AVPs, but now I have to check if they are
public or private.
So far our network uses only 192.168.x.x class for private servers.
Thanks for the quick reply
Uriel
On Fri, Mar 26, 2010 at 10:56 AM, Alex Balashov
<abalashov(a)evaristesys.com>wrote;wrote:
172.16.0.0/12 does not line up on octet boundaries.
You will need to do
something other than a regular expression. Fortunately, 'src_ip' is a
composite that supports comparisons against subnets in shorthand CIDR
notation.
It might also be that whatever you are trying to accomplish can be done
better some other way, but since you did not pose the question in terms of
the objective, I cannot speak to that.
--
Sent from mobile device
On Mar 26, 2010, at 9:46 AM, Uriel Rozenbaum <uriel.rozenbaum(a)gmail.com>
wrote:
Hi guys,
Does anyone have a REGEX syntax to match a private IP on the 192.168.x.x
range?
I'm trying with:
if($avp(s:ip_origen)=~"192.168(\.([1]?\d{1,2}|2[0-4]{1}\d{1}|25[0-5]{1})){2}"
)
But all IPs pass as private, even public ones.
Thanks!
Uriel
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