20 Jul
2004
20 Jul
'04
11:42 a.m.
Hey,
I can't help myself even with your advice and after reading the manual.
I've done what you told me and now my phones (pingtel xpressa) register. But
when I try to make a call, the INVITE does that way:
A->SER1->SER2
but nothing else, so the call can't be done.
This time, I'll try to be more patient, lol.
Thanks
Laurent
Selon Andrei Pelinescu-Onciul <pelinescu-onciul(a)fokus.fraunhofer.de>de>:
On Jul 19, 2004 at 14:22, l.gaillard01(a)free.fr
<l.gaillard01(a)free.fr> wrote:
No one can help me?
No ideas which can help me to do that?
You are very impatient, aren't you :-)
The answer is: yes you can do that quite easily.
Hints: - use record_route and loose_route on both sers
- use forward(ser2) on ser1
- use if (!src_ip==ser1) send error reply; break on ser2
- read the manual
(http://www.iptel.org/ser/doc/seruser/seruser.html)
Andrei
Selon l.gaillard01(a)free.fr:
>
> Hi all,
>
> I need to configure two ser servers to do such a thing :
>
> SER2 is the registrar proxy, knowing ips ...
> SER1 is a must go through proxy. Each packet must go through him before
being
> sent to SER2.
> ________ ________
> | | REGISTER | |
> Phone B ---->| |------------------>| |
> | SER1 | | SER2 |
> | | | |
> | IP .4 | REGISTER | IP .8 |
> Phone A ---->| |------------------>| |
> |_______ | |________|
>
>
> CALL from A to B
> ________ ________
> | | CALL | |
> Phone B <----| |<------------------| |
> | SER1 | | SER2 |
> | | | |
> | IP .4 | CALL | IP .8 |
> Phone A ---->| |------------------>| |
> |_______ | |________|
>
> When a call is done by A, it must go through ser1 then to ser2 and before
> coming back to phone B it must go to SER1.
>
> I can't find a way to do that with a script. If someone can help me, it
would
be
great.
Thanks,
Laurent
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