6 Jun
2011
6 Jun
'11
3:37 p.m.
Hello Iñaki,
I did this a long time ago using a db backend, i can't remember exactly how.
the table would be:
areacode, route
1 route1
13 route2
I connected to mysql and ran something like:
select * from routes where '$rU' like concat(areacode,'%') order by
len(areacode) desc limit 1;
that works perfectly
hope it helps
David
On Mon, Jun 6, 2011 at 10:25 AM, Iñaki Baz Castillo <ibc(a)aliax.net> wrote:
Hi, I wonder how feasible is the folowing:
I have a regular expresion like:
REGEXP = "^((1|20)|(13|3|4)|(5|6))"
There are 3 matching groups:
1) (1|20)
2) (13|3|4)
3) (5|6)
I want to match the RURI user, let's suppose $rU = "138787686223". In
this case the above regexp matches groups 1 and 2, but since group 2
matching is longest ("13" is longest than "1") I want to get value
2.
In case $rU = "999999" I need to get "null", in case $rU =
"1000022323" I need to get "1".
AFAIK there is no way to do it with current regular expression utils
in Kamailio, but maybe I miss something. Thanks a lot.
--
Iñaki Baz Castillo
<ibc(a)aliax.net>
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