8 Jul
2022
8 Jul
'22
3:31 p.m.
I`ve solved this issue. The condition if ($Ru == «*udp*:10.130.0.23:5070»)
was wrong.
Here is the correct code:
if ($Ru eq "sip:10.130.0.23:5070") {
$fs = "udp:10.130.0.23:5060";
} else {
$fs = "udp:10.130.0.23:5070";
}
пт, 1 июл. 2022 г. в 15:17, Алексей Якимкин <ayakimkin(a)gmail.com>om>:
Hello,
Are you ips (LAN_IP and WAN_IP) on sepparate interfaces?
I use add_path for Register requests. It insert header Path:
<sip:10.130.0.23:5070;lr>
My pbx calls to User-Agent throught 10.130.0.23:5070. INVITE(from
kamailio) go out to internet from 10.130.0.23:5070
This line "$fs = «udp:10.130.0.23:5060»;" don`t work, It produces an
error:
(pv [pv_branch.c:62]: pv_get_branchx_helper(): error accessing branch [0])
ср, 29 июн. 2022 г. в 18:55, ZZ Wave <zzwave(a)gmail.com>om>:
--
С уважением,
Якимкин Алексей
I use this with NATed Kamailio and Asterisk for
"transparent"
registrations:
if (is_method("REGISTER")) {
add_path();
}
if ($Ri=="LAN_IP") {
$fs="udp:WAN_IP:5060";
} else {
$fs="udp:LAN_IP:5060";
}
AFAIK FreeSwitch supports Path as well but Yate doesn't
ср, 29 июн. 2022 г. в 12:25, Алексей Якимкин <ayakimkin(a)gmail.com>om>:
--
С уважением,
Якимкин Алексей
Hello,
I have kamailio in local network behind NAT. Kamailio have one
interface eth1 with ip 10.130.0.23
UserAgent - (internet) - (178.0.0.169)router_with_NAT - (LAN) -
kamailio+rtpproxy - pbx
I made two listeners:
listen=udp:10.130.0.23:5070 #to pbx in lan (I don`t want to put via
header with 178.0.0.169)
listen=udp:10.130.0.23:5060 advertise 178.0.0.169:5060 #to internet
(UserAgent need to get via header with 178.0.0.169 )
mhomed = 1 # I think It not useful for my case
UserAgent send Register and Invite to 178.0.0.169:5060, Kamailio get it
on udp:10.130.0.23:5060
Kamailio Relay it to udp:10.130.0.23:5070
My pbx get requests from udp:10.130.0.23:5070 with via header
10.130.0.23
Responses to UserAgent go from udp:10.130.0.23:5060 with
via 178.0.0.169
In RELAY block:
if ($Ru == «udp:10.130.0.23:5070») {
#set_send_socket(«udp:10.130.0.23:5060»);
$fs = «udp:10.130.0.23:5060»;
#force_send_socket(«udp:10.130.0.23:5060»);
} else {
#set_send_socket(«udp:10.130.0.23:5070»);
$fs = «udp:10.130.0.23:5070»;
}
#$fs = «udp:10.130.0.23:5070»;
if (!t_relay()) {
sl_reply_error();
}
route[REGISTRAR] {
if ($rd == "mydomain.ru" || $rd == "mydomain2.ru") {
set_send_socket("udp:10.130.0.23:5070");
}
}
It works for requests from UserAgent to PBX. But INVITE from my pbx to
UserAgent goes only through udp:10.130.0.23:5070 , Kamailio realy it
to internet from udp:10.130.0.23:5070
I get error in syslog: (pv [pv_branch.c:62]: pv_get_branchx_helper():
error accessing branch [0])
I tried set_send_socket(«udp:10.130.0.23:5070»); and $fs =
«udp:10.130.0.23:5070»;
Why I can`t relay outgoing requests to internet through another socket?
--
Best regards,
Alex
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Important: keep the mailing list in the recipients, do not reply only to
the sender!
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