Thank you all that works just fine, my last step is to create an if statement to only enter to do this if the condition matches.


if($rU=~"XYZ") //where xyz is anything not 0-9 * and #
{             

$rU = $(rU{re.subst,/[^0-9*#]//g});

}

Regards


On Tue, Feb 12, 2013 at 10:42 AM, Daniel-Constantin Mierla <miconda@gmail.com> wrote:
Hello,


On 2/12/13 9:28 AM, Ali Jawad wrote:
Hi
Thanks, what I actually need is keep numbers and * and # and remove the rest, something like 

                $rU = $(rU{re.subst,/![0-9*#]//g});

But I am not sure that ! works for negation.
use [^0-9*#] for negation, see:

- http://www.regular-expressions.info/charclass.html

Cheers,
Daniel


Regards

On Mon, Feb 11, 2013 at 5:43 PM, Daniel Tryba <daniel@pocos.nl> wrote:
On Monday 11 February 2013 11:24:36 Ali Jawad wrote:
> I am using the below to strip "-" from destination numbers, it does work
> just fine "I replace - with nothing", what i need to do now is to strip all
> characters except 0-9 * and #. Is there anyway to do it using the following
> configuration part

You are using regular expression substitution, so yes this can be done:
/[^0-9*#]//g

Take a look at http://en.wikipedia.org/wiki/Regular_expression
for more info.






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