172.16.0.0/12 does not line up on octet boundaries. You will need to do something other than a regular expression. Fortunately, 'src_ip' is a composite that supports comparisons against subnets in shorthand CIDR notation.
It might also be that whatever you are trying to accomplish can be done better some other way, but since you did not pose the question in terms of the objective, I cannot speak to that.
-- Sent from mobile device
On Mar 26, 2010, at 9:46 AM, Uriel Rozenbaum uriel.rozenbaum@gmail.com wrote:
Hi guys,
Does anyone have a REGEX syntax to match a private IP on the 192.168.x.x range?
I'm trying with: if($avp(s:ip_origen)=~"192.168(.([1]?\d{1,2}|2[0-4]{1}\d{1}|25[0-5] {1})){2}" )
But all IPs pass as private, even public ones.
Thanks! Uriel _______________________________________________ Kamailio (OpenSER) - Users mailing list Users@lists.kamailio.org http://lists.kamailio.org/cgi-bin/mailman/listinfo/users http://lists.openser-project.org/cgi-bin/mailman/listinfo/users