22 May
2003
22 May
'03
9:12 p.m.
On Thursday 22 May 2003 21:47, Alejandro Olchik wrote:
Looking at the serctl rm command the followin shell script is found:
$0 acl revoke $1 > /dev/null 2>&1 $0 dul $1 > /dev/null 2>&1 ;;What does $0 dul $1... do?
Anybody knows?
It calls the script itself again with "dul" as first parameter and the old first as second parameter. But i do not find any other reference for dul in the script. So its probably an old and now useless statement, but it should not harm any way :-)
Regards Nils Ohlmeier