Good tutorial,
now that i see it, I think you can try using the following:
$` eq "Lord Wo"; $& eq "pp"; $' eq "er of Fibbing";
$rU = $(rU{re.subst,/^%23/$`$'}) so you get the match before and after the string, but you should try it first, I'm not sure if it will impact on the var and avp space.
The previous example matched some string followed by %23 and followed by some other string. Then the translaion only used the strings and forgot about the %23.
This one does the same without using internal REGEXP variables.
Glad I could help. Uriel
On Wed, Jan 13, 2010 at 5:23 AM, alex pappas rebel.pappas@gmail.com wrote:
Hi
I found this tutorial on internet http://www.comp.leeds.ac.uk/Perl/sandtr.html which is explaining in deep the sustitution.
Thank you Alex
On Wed, Jan 13, 2010 at 10:10 AM, alex pappas rebel.pappas@gmail.comwrote:
Hi,
That is very cool and it works :-)) Could you explain how the substitution is done so i can learn that and use it again?
Thank you Alex
On Tue, Jan 12, 2010 at 6:51 PM, Uriel Rozenbaum < uriel.rozenbaum@gmail.com> wrote:
Alex, I think you can use:
$rU = $(rU{re.subst,/^(.*)%23(.*)/\1\2/})
Maybe you should use some variable to make this modification.
Cheers, Uriel
On Tue, Jan 12, 2010 at 12:12 PM, alex pappas rebel.pappas@gmail.comwrote:
Hi
I fixed in this way:
if($rU =~ "^.*%+") { xlog("alx ------- The number contains %23 OR #"); $var(new_prefix) = $(rU{s.select,0,%}); # getthe prefix to re use it later $var(new_num) = $(rU{s.select,1,%}); # cat the % $var(cat_hash) = $(var(new_num){s.substr,2,0}); # cat the 23 $rU = $var(new_prefix) + $var(cat_hash); xlog("alx ------- The var(new_prefix) = $var(new_prefix) the var(new_num) = $var(new_num) new rU = $var(cat_hash) -------"); }
i don't know if is the best way but it works. If anyone can suggest something else less power consuming, is welcomed.
Cheers Alex
On Tue, Jan 12, 2010 at 4:49 PM, alex pappas rebel.pappas@gmail.comwrote:
Hi,
I already tried that and i was expecting to see back a # but that did not happen. Anyway i will read more carefully the docs and see if I find something there.
Cheers Alex
On Tue, Jan 12, 2010 at 4:41 PM, Alex Balashov < abalashov@evaristesys.com> wrote:
Section 19.1.2 ("Character Escaping Requirements") of RFC 3261 says quite clearly that special characters must be escaped when appearing in SIP URIs.
It's up to the SIP stack to decode them and translate them into something usable by the caller, if needed. Kamailio doesn't do this for '#' by default.
If you want to decode escaped characters, try use the transformations that are designed for that, i.e. {s.unescape.user}. Example:
$(rU{s.unescape.user})
On 01/12/2010 09:29 AM, alex pappas wrote:
Dear Friends, > > Do you have any idea on how to remove from $rU the %23 when is send > in > to my network? > The scenario is: The customer will send (prefix # number). This is > translated in sip in (prefix %23 number). I need to remove this in > order > to check against PDT module. > > Thanks > Alex > > > > > > _______________________________________________ > Kamailio (OpenSER) - Users mailing list > Users@lists.kamailio.org > http://lists.kamailio.org/cgi-bin/mailman/listinfo/users > http://lists.openser-project.org/cgi-bin/mailman/listinfo/users >
-- Alex Balashov - Principal Evariste Systems Web : http://www.evaristesys.com/ Tel : (+1) (678) 954-0670 Direct : (+1) (678) 954-0671
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