10 Jul
2019
10 Jul
'19
6:12 p.m.
Got it working by setting:
$var(account)=$(au{s.select,0,-}{s.toupper}) + "-" + $(au{s.select,1,-});
Thanks
În mie., 10 iul. 2019 la 15:13, Ilie Soltanici <iliusha.md(a)gmail.com> a
scris:
Hello,
Could someone help me to set a variable as a string in Kamailio?
At the moment i'm using the following statement:
*$var(account)=$(au{s.substr,0,8}); *
*xlogl("L_INFO", "[1234] Account: $var(* *account*
*)\n");*
which is working fine, but i need to change it into:
*$var(account)=$(au{s.select,0,-}{s.toupper})-$(au{s.select,1,-});*
By doing this I'm getting the error:
*[core/rvalue.c:1007]: rval_get_int(): automatic string to int conversion
for "AT" failed[core/rvalue.c:1912]: rval_expr_eval_int(): rval expression
conversion to int failed (729,30-729,59)*
I tried also:
*$var(account)="" +
"$(au{s.select,0,-}{s.toupper})-$(au{s.select,1,-})";*
But, then I'm getting:
*Account = $(au{s.select,0,-}{s.toupper})-$(au{s.select,1,-})*
instead of the value.
What is the correct way to set it?
Thank you.