Hello,
it is quite common to have a lookahead approach to match the longest
value, which looks like happening in your case for 2nd contact header.
We just leverage the libc regex functions, it is not a custom
implementation in Kamailio.
You should try to exclude having > in .+ matched value, maybe with a
regexp like:
@([^>]+)>
Cheers,
Daniel
On 25.11.22 22:15, Salvinder Parhar wrote:
Hi,
I'm trying to capture and substitute the host IP of contact header
using the subst_hf but it's not working as expected. I tested my regex
in a tester and it works fine there but not in the Kamailio config.
Regex: @(.+?)>
Substitution: @PUBLIC_IP:5060>
Three contact headers that I'm trying to match;
Contact:<sip:0065*7766@172.16.1.217:5060
<http://7766@172.16.1.217:5060>>;methods="INVITE,ACK,BYE,CANCEL,OPTIONS,INFO,MESSAGE,SUBSCRIBE,NOTIFY,PRACK,UPDATE,REFER"
Contact:
<sip:0065*7788@172.16.1.216;transport=udp>;expires=3600;reg-id=1;+sip.instance="<urn:uuid:03660bc5-bb70-4784-8ac5-000413B108BA>"
Contact: <sip:0925*0007@172.16.1.218:5060 <http://0007@172.16.1.218:5060>>
Outcome I'm expecting for the three contact headers;
Contact:<sip:0065*7766@PUBLIC_IP:5060>;methods="INVITE,ACK,BYE,CANCEL,OPTIONS,INFO,MESSAGE,SUBSCRIBE,NOTIFY,PRACK,UPDATE,REFER"
Contact:
<sip:0065*7788@PUBLIC_IP:5060>;expires=3600;reg-id=1;+sip.instance="<urn:uuid:03660bc5-bb70-4784-8ac5-000413B108BA>"
Contact: <sip:0925*0007@PUBLIC_IP:5060>
This regex in Kamailio works fine for the first and third contact
header but for the second contact header it matches all the way to the
end of the contact header excluding the quote (") sign. I've tried so
many other combinations [like @(.+?)>;? ] of regex but nothing seems
to work.
Is there a way to accomplish this with one regex?
Thanks,
Sal
On Fri, 25 Nov 2022 at 16:10, Salvinder Parhar
<salvinder.parhar09(a)gmail.com> wrote:
Hi,
I'm trying to capture and substitute the host IP of contact header
using the subst_hf but it's not working as expected. I tested my
regex in a tester and it works fine there but not in Kamailio config.
*Regex:* @(.+?)>
*Substitution:* @PUBLIC_IP:5060>
*Three contact headers that I'm trying to match;*
Contact:<sip:0065*7766@199.48.100.166:5060
<http://7766@199.48.100.166:5060>>;methods="INVITE,ACK,BYE,CANCEL,OPTIONS,INFO,MESSAGE,SUBSCRIBE,NOTIFY,PRACK,UPDATE,REFER"
Contact:
<sip:0065*7788@172.16.1.216;transport=udp>;expires=3600;reg-id=1;+sip.instance="<urn:uuid:03660bc5-bb70-4784-8ac5-000413B108BA>"
Contact: <sip:0925*0007@199.48.100.166:5060
<http://0007@199.48.100.166:5060>>
*Outcome I'm expecting for the three contact headers;*
Contact:<sip:0065*7766*@PUBLIC_IP:5060>*;methods="INVITE,ACK,BYE,CANCEL,OPTIONS,INFO,MESSAGE,SUBSCRIBE,NOTIFY,PRACK,UPDATE,REFER"
Contact:
<sip:0065*7788*@PUBLIC_IP:5060>*;expires=3600;reg-id=1;+sip.instance="<urn:uuid:03660bc5-bb70-4784-8ac5-000413B108BA>"
Contact: <sip:0925*0007*@PUBLIC_IP:5060>*
This regex in Kamailio works fine for the first and third contact
header but for the second contact header it matches all the way to
the end of the contact header excluding the quote (") sign. I've
tried so many other combinations [like *(a)(.+?)>;?* ] of regex but
nothing seems to work.
Is there a way to accomplish this with one regex?
Thanks,
Sal
*
*
*
*
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