Hi

Thanks, what I actually need is keep numbers and * and # and remove the rest, something like 

                $rU = $(rU{re.subst,/![0-9*#]//g});

But I am not sure that ! works for negation.

Regards

On Mon, Feb 11, 2013 at 5:43 PM, Daniel Tryba <daniel@pocos.nl> wrote:

On Monday 11 February 2013 11:24:36 Ali Jawad wrote:
> I am using the below to strip "-" from destination numbers, it does work
> just fine "I replace - with nothing", what i need to do now is to strip all
> characters except 0-9 * and #. Is there anyway to do it using the following
> configuration part

You are using regular expression substitution, so yes this can be done:
/[^0-9*#]//g

Take a look at http://en.wikipedia.org/wiki/Regular_expression
for more info.

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