12 Feb
2013
12 Feb
'13
9:42 a.m.
Hello,
On 2/12/13 9:28 AM, Ali Jawad wrote:
Hi
Thanks, what I actually need is keep numbers and * and # and remove
the rest, something like
$rU = $(rU{re.subst,/![0-9*#]//g});
But I am not sure that ! works for negation.
use [^0-9*#] for negation, see:
- http://www.regular-expressions.info/charclass.html
Cheers,
Daniel
Regards
On Mon, Feb 11, 2013 at 5:43 PM, Daniel Tryba <daniel(a)pocos.nl
<mailto:daniel@pocos.nl>> wrote:
On Monday 11 February 2013 11:24:36 Ali Jawad wrote:
--
Daniel-Constantin Mierla - http://www.asipto.com
http://twitter.com/#!/miconda - http://www.linkedin.com/in/miconda
Kamailio World Conference, April 16-17, 2013, Berlin
- http://conference.kamailio.com -
I am using the below to strip "-" from
destination numbers, it
does work
just fine "I replace - with nothing",
what i need to do now is
to strip all
characters except 0-9 * and #. Is there anyway to
do it using
the following
configuration part
You are using regular expression substitution, so yes this can be
done:
/[^0-9*#]//g
Take a look at http://en.wikipedia.org/wiki/Regular_expression
for more info.
*
*
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