Hello,
Suppose I have $var(a) = 1234#5678 and $var(b)=123455667
I need to get the number before '#' character if exists , meaning that from $var(a) I must get 1234# and from $var(b) I must get empty string.
I tried $var(pref)= $(var(a){s.select,0,#}); but I'm getting the whole string if # doesn't exists.
There is a way to check if # exists by subtracting the length of the string before and after removing # character and check if length changes , but I want a cost-less method.
Any help would be appreciated.
Thanks
Ali
On Monday 22 June 2015 13:58:28 Ali Taher wrote:
I tried $var(pref)= $(var(a){s.select,0,#}); but I'm getting the whole string if # doesn't exists.
There is a way to check if # exists by subtracting the length of the string before and after removing # character and check if length changes , but I want a cost-less method.
So just check for: $var(pref)= $(var(a){s.select,0,#}); if($var(pref)==$var(a)) { var(pref)=""; }
This would cost near to nothing.
On 22/06/15 16:16, Daniel Tryba wrote:
On Monday 22 June 2015 13:58:28 Ali Taher wrote:
I tried $var(pref)= $(var(a){s.select,0,#}); but I'm getting the whole string if # doesn't exists.
There is a way to check if # exists by subtracting the length of the string before and after removing # character and check if length changes , but I want a cost-less method.
So just check for: $var(pref)= $(var(a){s.select,0,#}); if($var(pref)==$var(a)) { var(pref)=""; }
This would cost near to nothing.
In general the operations in memory are very fast, so even on high load you will barely notice any impact no mater the variant you try to use.
For sake of completion and showing alternatives, you can use regexp to see if # is in the value or not:
if($var(a) =~ "#") { # - the char # is inside $var(a) ... } else { ... }
Cheers, Daniel
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Ali Taher -
Daniel Tryba -
Daniel-Constantin Mierla