Am 22.03.2010 14:13, schrieb Uriel Rozenbaum:

Hey, thanks for both replies from Daniel and Klaus.

Klaus, will this work on kamailio 1.5.3 the same way?

AFAIK: yes

Daniel, sorry I misstyped. The first flags should be ocfaei and the second ones ocfaie.

What I meant with the question is: I receive an invite from public IP; I call force_rtp_proxy("ocfaei"); Then I receive the reply (lets say 183 or 200) and I call force_rtp_proxy("ocfaie");

Is this right?

No, read the description:

'i' corresponds to rtpproxy's first interface 'e' corresponds to rtpproxy's second interface.

so you should use: rtpproxy -l PRIVATE_IP/PUBLIC_IP

Then, the force_rtp_proxy calls should work.

Further: if the client in the public network is behind NAT you should not use the 'a' flag.

regards klaus

Thanks in advance, Uriel

On Mon, Mar 22, 2010 at 6:20 AM, Klaus Darilion <klaus.mailinglists@pernau.at mailto:klaus.mailinglists@pernau.at> wrote:

Recently I have rewritten the documentation about using the e/i
flag. See

http://sip-router.org/docbook/sip-router/branch/master/modules_k/nathelper/nathelper.html#id2907572

regards
klaus

Am 19.03.2010 22:12, schrieb Uriel Rozenbaum:

    Hi guys,

    I have some easy doubt about nathelper functions using RTPProxy.

    I'm trying to bridge from an external IP to an internal IP.
    The start-line for rtpproxy is: rtpproxy -l PUBLIC_IP/PRIVATE_IP -s
    udp:127.0.0.1:7999 <http://127.0.0.1:7999>
    <http://127.0.0.1:7999> -F

    It starts OK and I see it when kamailio starts.

    I'm going to use something like Daniel showed on some other mail:

    if(dst_ip==private)
        force_rtp_proxy("ocfaei");
    else
        force_rtp_proxy("ocfaei");

    if i have the invite from a public IP to someone in private on the
    request I'll run
    force_rtp_proxy("ocfaei");
    then the reply will be from private to public... should I run
    "force_rtp_proxy("ocfaei");"? or should it be the same?

    As allways, thanks for your help.

    Kind regards,
    Uriel



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