2 Jul
2018
2 Jul
'18
3:52 p.m.
Hi ,
Can someone explain me what is \1 and \3 doing in the subst expression
?
Input : From: <sip:anonymous@10.211.160.168
;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD
subst('/^From:(.*)10.211.160.168(.*)>(.*)/From:\110.211.160.174>\3/ig');
Output : From: <sip:anonymous@10.211.160.174
;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD
Regards,
Mahesh.b
2 Jul
2 Jul
4:24 p.m.
They are references to groups in the regex match. The groups are in
parenthesis. Whatever is matched by group 1 and 3 will be included in the
substitution.
https://regexr.com/ and https://regex101.com/ are both good sites for
building and explaining regexes.
4:40 p.m.
Thanks John for the Reply.
So if i understand properly :
group 1 is here <sip:anonymous@
group 2 is empty
group 3 is ;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD
the previous expression is working for IPv4.
Now for IPv6
Input : From: <sip:anonymous@
[2008:abcd:1234:2260:208:5dff:fe93:5b65]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
subst('/^From:(.*)[2008:abcd:1234:2260:208:5dff:fe93:5b65](.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig');
Output : From:
<sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b6[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
//what is going wrong here?
Here
group 1 is <sip:anonymous@
group 2 is empty
group 3 is ;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
what mistake am i making for IPv6 ? if you see the output.
Regards,
Mahesh.b
On Mon, Jul 2, 2018 at 6:54 PM John Petrini <jpetrini(a)coredial.com> wrote:
They are references to groups in the regex match. The
groups are in
parenthesis. Whatever is matched by group 1 and 3 will be included in the
substitution.
https://regexr.com/ and https://regex101.com/ are both good sites for
building and explaining regexes.
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sr-users(a)lists.kamailio.org
https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
5:09 p.m.
I think i found the reason, it needs a \ before [ , could you please tell
me whats the syntax to put the replacement expression in this page?
[image: image.png]
Regards,
Mahesh.B
On Mon, Jul 2, 2018 at 7:10 PM mahesh b <mahesh.b.2487(a)gmail.com> wrote:
Thanks John for the Reply.
So if i understand properly :
group 1 is here <sip:anonymous@
group 2 is empty
group 3 is ;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD
the previous expression is working for IPv4.
Now for IPv6
Input : From: <sip:anonymous@
[2008:abcd:1234:2260:208:5dff:fe93:5b65]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
subst('/^From:(.*)[2008:abcd:1234:2260:208:5dff:fe93:5b65](.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig');
Output : From:
<sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b6[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
//what is going wrong here?
Here
group 1 is <sip:anonymous@
group 2 is empty
group 3 is ;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
what mistake am i making for IPv6 ? if you see the output.
Regards,
Mahesh.b
On Mon, Jul 2, 2018 at 6:54 PM John Petrini <jpetrini(a)coredial.com> wrote:
They are references to groups in the regex match.
The groups are in
parenthesis. Whatever is matched by group 1 and 3 will be included in the
substitution.
https://regexr.com/ and https://regex101.com/ are both good sites for
building and explaining regexes.
_______________________________________________
Kamailio (SER) - Users Mailing List
sr-users(a)lists.kamailio.org
https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
5:21 p.m.
Your first group is matching From:
<sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b6
but it looks like you want it to only match <sip:anonymous@. Try escaping
the brackets, the regex engine is interpreting them as a list instead of
matching the literal "[]" characters.
subst('/^From:(.*)\[2008:abcd:1234:2260:208:5dff:fe93:5b65\](
.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig');
John Petrini
Platforms Engineer
[image: Call CoreDial] 215.297.4400 x 232 <215-297-4400>
[image: Call CoreDial] www.coredial.com <https://coredial.com/>
[image: CoreDial] 751 Arbor Way, Hillcrest I, Suite 150 Blue Bell, PA 19422
<https://www.google.com/maps/place/CoreDial,+LLC/@40.140902,-75.2878857,17z/data=!3m1!4b1!4m5!3m4!1s0x89c6bc587f1cfd47:0x4c79d505f2ee580b!8m2!3d40.140902!4d-75.285697>
The information transmitted is intended only for the person or entity to
which it is addressed and may contain confidential and/or privileged
material. Any review, retransmission, dissemination or other use of, or
taking of any action in reliance upon, this information by persons or
entities other than the intended recipient is prohibited. If you received
this in error, please contact the sender and delete the material from any
computer.
On Mon, Jul 2, 2018 at 9:40 AM, mahesh b <mahesh.b.2487(a)gmail.com> wrote:
Thanks John for the Reply.
So if i understand properly :
group 1 is here <sip:anonymous@
group 2 is empty
group 3 is ;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD
the previous expression is working for IPv4.
Now for IPv6
Input : From: <sip:anonymous@[2008:abcd:
1234:2260:208:5dff:fe93:5b65]>;tag=42006C96_nab_FFFF_isp_
FFFF_cco_FFFF_igo_FFFF_mgt_8092
subst('/^From:(.*)[2008:abcd:1234:2260:208:5dff:fe93:5b65](
.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig');
Output : From: <sip:anonymous@[2008:abcd:
1234:2260:208:5dff:fe93:5b6[2008:abcd:1234:2260:20c:29ff:
fe9a:b9cb]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
//what is going wrong here?
Here
group 1 is <sip:anonymous@
group 2 is empty
group 3 is ;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
what mistake am i making for IPv6 ? if you see the output.
Regards,
Mahesh.b
On Mon, Jul 2, 2018 at 6:54 PM John Petrini <jpetrini(a)coredial.com> wrote:
They are references to groups in the regex match.
The groups are in
parenthesis. Whatever is matched by group 1 and 3 will be included in the
substitution.
https://regexr.com/ and https://regex101.com/ are both good sites for
building and explaining regexes.
_______________________________________________
Kamailio (SER) - Users Mailing List
sr-users(a)lists.kamailio.org
https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
_______________________________________________
Kamailio (SER) - Users Mailing List
sr-users(a)lists.kamailio.org
https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
5:34 p.m.
it is subst('/
^From:(.*)\[2008:abcd:1234:2260:208:5dff:fe93:5b65\](.*)>(.*)/From:\1\[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb\]>\3
/ig');
Thank you!
On Mon, Jul 2, 2018 at 7:52 PM John Petrini <jpetrini(a)coredial.com> wrote:
Your first group is matching From:
<sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b6
but it looks like you want it to only match <sip:anonymous@. Try escaping
the brackets, the regex engine is interpreting them as a list instead of
matching the literal "[]" characters.
subst('/^From:(.*)\[2008:abcd:1234:2260:208:5dff:fe93:5b65\](.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig');
John Petrini
Platforms Engineer
[image: Call CoreDial] 215.297.4400 x 232 <215-297-4400>
[image: Call CoreDial] www.coredial.com <https://coredial.com/>
[image: CoreDial] 751 Arbor Way, Hillcrest I, Suite 150 Blue Bell, PA
19422
<https://www.google.com/maps/place/CoreDial,+LLC/@40.140902,-75.2878857,17z/data=!3m1!4b1!4m5!3m4!1s0x89c6bc587f1cfd47:0x4c79d505f2ee580b!8m2!3d40.140902!4d-75.285697>
The information transmitted is intended only for the person or entity to
which it is addressed and may contain confidential and/or privileged
material. Any review, retransmission, dissemination or other use of, or
taking of any action in reliance upon, this information by persons or
entities other than the intended recipient is prohibited. If you received
this in error, please contact the sender and delete the material from any
computer.
On Mon, Jul 2, 2018 at 9:40 AM, mahesh b <mahesh.b.2487(a)gmail.com> wrote:
Thanks John for the Reply.
So if i understand properly :
group 1 is here <sip:anonymous@
group 2 is empty
group 3 is ;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD
the previous expression is working for IPv4.
Now for IPv6
Input : From: <sip:anonymous@
[2008:abcd:1234:2260:208:5dff:fe93:5b65]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
subst('/^From:(.*)[2008:abcd:1234:2260:208:5dff:fe93:5b65](.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig');
Output : From:
<sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b6[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
//what is going wrong here?
Here
group 1 is <sip:anonymous@
group 2 is empty
group 3 is ;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
what mistake am i making for IPv6 ? if you see the output.
Regards,
Mahesh.b
On Mon, Jul 2, 2018 at 6:54 PM John Petrini <jpetrini(a)coredial.com>
wrote:
_______________________________________________
Kamailio (SER) - Users Mailing List
sr-users(a)lists.kamailio.org
https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
They are references to groups in the regex match.
The groups are in
parenthesis. Whatever is matched by group 1 and 3 will be included in the
substitution.
https://regexr.com/ and https://regex101.com/ are both good sites for
building and explaining regexes.
_______________________________________________
Kamailio (SER) - Users Mailing List
sr-users(a)lists.kamailio.org
https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
_______________________________________________
Kamailio (SER) - Users Mailing List
sr-users(a)lists.kamailio.org
https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
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