RE: [Serusers] Question on How Start MEDIAPROXY. - sr-users

8 Feb 2005


      Hello.
    For those who have the same problem i have found a "work-around"
solution.
In the pyhton file, for example mediaproxy.py, there is a #! at the
beggining of the file with the route to the bin.  You have to change this
for :
[prompt %]which pyhton2.3
/usr/local/bin/python2.3
this path is replaced in the mediaproxy.py file :
#!/usr/local/bin/python2.3
'''Provides a RTP Proxy server to be used in conjunction with SER's
mediaproxy
module. MediaProxy stands in between the 2 SIP clients participating in a
VoIP
conversation and forwards the RTP and RTCP streams between them, allowing
the SIP clients to work behind NAT without special settings on their behalf.
MediaProxy must have a public IP.
'''
....
at least that works for me ! 
Goos Luck.
Ricardo Javier Martinez Ogalde
Ingeniero de Desarrollo
VOISS NET S.A.
Cisco Certified Network Associate
*   :  (56 2) 240 81 96
*    :  (56 2) 245 74 95
*   :  rmartinez@redvoiss.net
...
-----Mensaje original-----
De: Ricardo Martinez [mailto:rmartinez@redvoiss.net]
Enviado el: Martes, 08 de Febrero de 2005 13:03
Para: 'serusers@lists.iptel.org'
Asunto: [Serusers] Question on How Start MEDIAPROXY.
Hello list.
   I have a question on How to Start Mediaproxy server.  
When i start
mediaproxy from the console i obtain the following error:
[root@sipproxy mediaproxy]# ./mediaproxy.py                  
  File "./mediaproxy.py", line 84
    print >>sys.stderr, "Mediaproxy error: %s. Exiting." % why
           ^
SyntaxError: invalid syntax
however i have installed Python2.3 
[root@sipproxy mediaproxy]# python
python     python1.5  python2    python2.2  python2.3
When i start mediaproxy with the next lines it works ok :
[root@sipproxy mediaproxy]# python2.3 mediaproxy.py
So i made a test and i started mediaproxy with the original python.
[root@sipproxy mediaproxy]# python mediaproxy.py     
  File "mediaproxy.py", line 84
    print >>sys.stderr, "Mediaproxy error: %s. Exiting." % why
           ^
SyntaxError: invalid syntax
And i obtained the same initial error.
My question is : Is there a way to force mediaproxy to start with the
pyhton2.3? and therefore make mediaproxy start with 
%./mediaproxy.py and
pyhton2.3
Hope that someone can help me here.
Thanks in advance,
Ricardo Martinez.-

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